MIAMI, Florida, CMC – Jamaica’s Reggae Boyz have been drawn alongside CONCACAF powerhouses United States in this year’s Gold Cup group stage.
In fixtures announced Friday by organizers for the June 24 to July 4 campaign in the United States and Canada, the Caribbean giant’s Jamaica was pitted in Group A against the seven-time reigning champions, along with Nicaragua.
The fourth team in the group will be finalized following the qualifiers, which run from June 16-20 and involve 12 teams, including Trinidad and Tobago, Guyana, Grenada, and St Kitts and Nevis.
Jamaica has never won the Gold Cup but reached back-to-back finals in 2015 and 2017 when they lost to Mexico and the United States, respectively.
They were knocked out in the quarter-finals by the United States in the tournament’s last edition two years ago.
Meanwhile, French Caribbean side Haiti has been drawn in Group B alongside eight-time champions Mexico, Honduras, and Asian Cup Champions Qatar.
Group C comprises Costa Rica, Panama, El Salvador, and a yet-to-be-determined qualifier. At the same time, Group D will also include a nation from the qualifiers, along with Canada, Guatemala, and Cuba.
In round one of the preliminaries, Trinidad and Tobago will meet the French Caribbean nation Guadeloupe in their bid to reach the group stage. Still, they must first get past the winners of the clash between Guyana and Grenada in round two.
St Lucia will take on Martinique, with the winners meeting the winners of the Suriname/Puerto Rico fixture. At the same time, St Kitts face Curacao hoping to reach round two, where the winners of French Guiana versus Sint Maarten await.
If Trinidad and Tobago, Guyana, and Grenada advance to the group stage, they will join Jamaica in Group A.
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